"One Giant Leap"
('The Jump' in terms of Conservation of Energy)

Equestrian Jumping, as a sport, can be broken down into a series of single jumps which are then combined together with both changes of direction and series' of multiple jumps.  These variations, with the addition of height, provide the different degrees of difficulty associated with 'jumping'.  The jump itself can be viewed in three parts:

These three pieces combine to create that 'flying' sensation, but it is definitely not a simple process!  The most important thing in jumping a horse is regulating the speed of the horse on approach so that the horse has enough energy to clear the full height of the fence.  Now riders don't carry odometers on their wrists, but this page will examine the speed required to clear a fence based on the principle of conservation of energy.
 

The Approach
 

                                                        KE = 1/2mv2

The Jump
 

                                                       PE = mgy

The Landing
 

                                                    KEf = 1/2mvf2

Using conservation of Energy, the jump can be divided into two parts; the first part (which will include 'The Approach' and 'The Jump') will show that the initial Kinetic Energy, KEi, can be set equal to the Potential Energy at the top of the jump and, using a known height, we can determine the necessary initial velocity.  The second part (which will include 'The Jump' and 'The Landing') will show that the Potential Energy, PE, can be set equal to the final Kinetic Energy, KEf, to determine the landing speed, vf.



Now, for some numbers . . . If a rider wishes to jump a 5 foot fence, how fast will they need to be going on 'approach'? Also, If horse and rider do clear the fence, how fast will they be going on 'landing'?

        Part One:                                     KEi = PE
                                                   1/2 mv2 = mgy

                                                    1/2v2 = 0.8(9.8m/s2*1.52m)
                                                         vlow = 6.1m/s
                                                     vhigh = 6.4m/s

      Part Two:                                   PE = KEf
                                                      mgy = 1/2 mv2

                                   9.8m/s2*1.52m = 0.8(1/2v2)
                                                    vlow = 4.88m/s
                                                     vhigh = 5.12m/s
 

A few other 'Horsey Notes' :



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*All photos from The Olympic Equestrian Site *
This page lovingly maintained by erinr@email.unc.edu
 
 

12-April-2003